Jets LB Jordan Jenkins was named the AFC defensive player of the week after his stellar play against the Bills last Thursday.
Jenkins recorded two tackles for losses and two sacks -- one being a strip sack on Bills QB Tyrod Taylor.
It is the first time Jenkins has received the honor, and the first time a Jets linebacker received it since David Harris in 2011.
Jenkins has 22 combined tackles, two sacks, one forced fumble, and one fumble recovery in nine games this season.
Bent, theJetsBlog.com Follow on Twitter
This was a breakout game of sorts for Jenkins, who entered the game with no sacks but was opportunistic on Thursday night, closing well and finishing strong on each of his big plays. Last season, Jenkins didn't record any sacks until week 14 but ended up with 2.5 in the last four games so hopefully something similar will happen over the rest of the season now that the seal has been broken.
Jenkins' main contributions to this team have been from his disciplined play, as he's been avoiding mistakes and setting the edge so that others can make plays. This happened on Thursday night where he got some upfield penetration so that the running back had nowhere to go and was stuffed for a loss by Darron Lee.
Ironically, despite winning the award, he had a few uncharacteristic mistakes in the Bills game, including one where he lost outside contain on a run that was bounced to the edge. He was also beaten for a potential touchdown in coverage, only for that pass to be dropped.
The next step for Jenkins will be to make impact plays while also keeping his number of negative plays at a minimum. That's something Lee has started to do and the pair will continue to earn plaudits and improve the efficiency of the defense as a whole if they can sustain that.